Csir net june 2018: Real analysis Question (1)

General Mathematics
Question:

Given $(x_n)$ is convergent sequence in $\mathbb{R}$ and $(y_n)$ is bounded sequence in $\mathbb{R}$ then we can conclude that,

(a) $(x_n+y_n)$ is convergent.
(b) $(x_n+y_n)$ is bounded.
(c) $(x_n+y_n)$ has no convergent subsequence.
(d)$(x_n+y_n)$ has no bounded subsequence.

Solution: we discuss options one by one

(a) take $x_n=1$ for all $n\in\mathbb{N}$ and $y_n=(-1)^n$ for all $n\in\mathbb{N}$ then, sequence $(x_n)$ is convergent and $(y_n)$ is bounded. But, $(x_n+y_n)=(0,2,0,2,0,2,....)$ which is not convergent. Hence (a) is false.

(b) given that sequence $(x_n)$ is convergent and hence it is bounded. Also given that, $(y_n)$ is bounded. So that sum of two bounded sequence $(x_n+y_n)$ is also bounded. Hence (b) is true.

(c), (d): By option (b) as sequence $(x_n+y_n)$ is bounded sequence and hence by "Bolzano Weierstrass theorem for sequences", it has convergent (hence bounded) subsequence. 
So that, (c),(d) are false. 

Hence answer is option (b) only. 













 

Comments

Popular posts from this blog

IIT-JAM 2018 Abstract Algebra Question (3)

IIT JAM 2019 Abstract Algebra: Question (2)

Question on Negation of Definition of limit of Sequence